Question

Question #9056d

Answer 1

I count four different trisaccharides that can be produced by the incomplete hydrolysis of amylopectin.

Explanation:

Amylopectin is a highly branched polymer of glucose. Its partial structure is

(Adapted from smartkitchen.com)

I have labelled five of the glucose units as `"A, B, C, D"`, and `"E"`.

The possible trisaccharide combinations are `"ABC, DEB, EBC"`, and `"ABE"`.

α-Maltotriose (Rings `"A, B, C"`)

α-Maltotriose is formed from rings `"A, B"`, and `"C"`.

It consists of three glucose units joined by α-(1→4) linkages.

α-Isomaltotriose

Isomaltose is formed from rings `"D, E"`, and `"B"`.

It consists of three glucose units joined by an α-(1→4) and an α-(1→6) linkage.

α-Panose

α-panose is formed from rings `"E, B"`, and `"C"`.

Adapted from www.chegg.com

It consists of three two glucose units joined by an α-(1→6) and an α-(1→4) linkage.

α-Isopanose

α-Isopanose is formed from rings `"A, B"`, and `"E"`.

The `"A"` and `"B"` rings are joined by an α-(1-4) linkage, while the `"E"` and `"B"` rings are joined by an α-(1→6) linkage.