What are the components of the vector between the origin and the polar coordinate (-8, (5pi)/3)(−8,5π3)?

1 Answer
bp
Feb 6, 2016

-4i +4sqrt3 j−4i+4√3j

Explanation:

In cartesian coordinates x= rcos thetax=rcosθ. In this case it would be x=-8 cos ((5pi)/3)= -8cos (-pi/3)= -4x=−8cos(5π3)=−8cos(−π3)=−4 and y= r sin theta= -8 sin((5pi)/3)= -8 sin (-pi/3)= 4sqrt3 y=rsinθ=−8sin(5π3)=−8sin(−π3)=4√3. The point would lie in 2nd quadrant.

Its vector form would be -4i +4sqrt3 j−4i+4√3j

Related questions
See all questions in Component Vectors
Impact of this question
1371 views around the world
You can reuse this answer
Creative Commons License