Question

What torque would have to be applied to a rod with a length of `8 m` and a mass of `8 kg` to change its horizontal spin by a frequency `15 Hz` over `4 s`?

Answer 1

`L=-1408*pi`

Explanation:

`alpha :"angular acceleration"`
`L: "Torque"`
`I: "moment of inertia"`
`"Torque is given by formula": L=alpha *I`
`L=2*pi(omega_l-omega_i)/(Delta t)*I`
`L=2*pi(4-15)/4 *I`
`L=-11 *pi/4 *I`
`I=m*r^2`
`I=8*64=512`
`L=-11*pi/4 *512`
`L=-11*128*pi`
`L=-1408*pi`