Question

An object with a mass of `3 kg` is traveling in a circular path of a radius of `15 m`. If the object's angular velocity changes from `5 Hz` to `3Hz` in `5 s`, what torque was applied to the object?

Answer 1

`L=-540pi`

Explanation:

`alpha=L/I`
`alpha": angular acceleration"`
`"L:torque"`
`"I:moment of inertia"`
`alpha=(omega_2-omega_1)/ (Delta t)`
`alpha=(2 pi*3-2 pi*5)/5`
`alpha=-(4pi)/5`
`I=m*r^2`
`I=3*15^2`
`I=3*225=675`
`L=alpha*I`
`L=-4pi/5*675`
`L=-540pi`