How many oxygen atoms are in $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ ?

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How many oxygen atoms are in $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ ?

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Answer 1 · 2016-02-13T22:37:17

There are 12 oxygen atoms in $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ .

Explanation:

In $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ , the subscript of three next to the $S O_{4}$ $SO_4$ polyatomic ion refers to the number of that same ion is in this molecule. Since there are four atoms of oxygen in each $S O_{4}$ $SO_4$ , indicated by the subscript of four next to the oxygen, and there are three $S O_{4}$ $SO_4$ ions, $4 \cdot 3 = 12$ $4*3= 12$ oxygen atoms present in $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ .

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How many oxygen atoms are in $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ ?

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How many oxygen atoms are in Al2(SO4)3Al_2(SO_4)_3?

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How many oxygen atoms are in $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ ?