How do you solve for a in # SA=2ab+2ac+2bc #?

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Answer 1 · 2016-02-15T03:13:20

Put the terms that contain a's alone on one side of the equation and factor out the a.

#SA - 2bc = 2ab + 2ac#

#SA - 2bc = 2a(b + c)#

#(SA - 2bc)/(b + c) = 2a#

#(SA - 2bc)/(2b + 2c) = a#

Practice Exercises:

a) #2xy + 3yz = 5xyz - 4y#

b) #sqrt(3x + 2y) = 2x - 4xz#

Good luck!