A barometer is filled with a cylindrical column of mercury that is #76.0# #cm# high and #1.0# #cm# in diameter. If the density of mercury is #13.53# #g##/##cm^3#, what is the mass of mercury in the column?

Question

9930 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-15T20:18:12

Approx. #1# #kg#.

We need to (i) find the volume of mercury; and (ii) convert this volume into a mass by use of the quoted density.

#"Volume of mercury"# #=# #76.0*cmxxpixx(0.5*cm)^2# #=# #59.7# #cm^3#. (Here we work out the volume of the mercury cylinder.)

Now that we have the volume, it is a simple matter to find the mass by multiplying the volume by the density:

#59.7# #cancel(cm^3)# #xx# #13.53# #g# #cancel(cm^-3)# #=# #??# #g#