Question

A gas occupies 12.3 L at a pressure of 40.0 mm Hg. What is the volume when the pressure is increased to 60.0 mm Hg?

Answer 1

At constant temperature `P_1V_1=P_2V_2`.

Explanation:

So, `V_2=(P_1V_1)/P_2` `=` `(40*"mm Hg"xx12.3*L)/(60*"mm Hg")` `~=` `8` `L`.

That volume is reduced is reasonable, inasmuch as the gas has been compressed.