A triangle has sides A, B, and C. Sides A and B have lengths of 9 and 3, respectively. The angle between A and C is $\frac{13 π}{24}$ $(13pi)/24$ and the angle between B and C is $\frac{π}{8}$ $(pi)/8$ . What is the area of the triangle?

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A triangle has sides A, B, and C. Sides A and B have lengths of 9 and 3, respectively. The angle between A and C is $\frac{13 π}{24}$ $(13pi)/24$ and the angle between B and C is $\frac{π}{8}$ $(pi)/8$ . What is the area of the triangle?

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Answer 1 · 2016-02-19T09:07:17

use the formula area = $\frac{1}{2} A . B sin θ$ $1/2A.Bsintheta$

Explanation:

here the angle between sides Aand B = $θ$ $theta$
So, $θ = π - 13 \frac{π}{24} - \frac{π}{8} = π - 16 \frac{π}{24} = \frac{π}{3}$ $theta=pi-13pi/24-pi/8= pi-16pi/24=pi/3$
Hence area = $\frac{1}{2} \cdot 9 \cdot 3 \cdot sin (\frac{π}{3})$ $1/2*9*3*sin(pi/3)$ = 6.75 squnit

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A triangle has sides A, B, and C. Sides A and B have lengths of 9 and 3, respectively. The angle between A and C is $\frac{13 π}{24}$ $(13pi)/24$ and the angle between B and C is $\frac{π}{8}$ $(pi)/8$ . What is the area of the triangle?

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A triangle has sides A, B, and C. Sides A and B have lengths of 9 and 3, respectively. The angle between A and C is (13pi)/2413π24(13pi)/24 and the angle between B and C is (pi)/8π8 (pi)/8. What is the area of the triangle?

1 Answer

Explanation:

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A triangle has sides A, B, and C. Sides A and B have lengths of 9 and 3, respectively. The angle between A and C is $\frac{13 π}{24}$ $(13pi)/24$ and the angle between B and C is $\frac{π}{8}$ $(pi)/8$ . What is the area of the triangle?