A triangle has sides A, B, and C. Sides A and B have lengths of 9 and 3, respectively. The angle between A and C is $(13pi)/24$ and the angle between B and C is $(pi)/8$ . What is the area of the triangle?

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Answer 1 · 2016-02-19T09:07:17

use the formula area = $1/2A.Bsintheta$

here the angle between sides Aand B = $theta$
So, $theta=pi-13pi/24-pi/8= pi-16pi/24=pi/3$
Hence area = $1/2*9*3*sin(pi/3)$ = 6.75 squnit

A triangle has sides A, B, and C. Sides A and B have lengths of 9 and 3, respectively. The angle between A and C is (13pi)/24(13pi)/24 and the angle between B and C is (pi)/8 (pi)/8. What is the area of the triangle?