Question

What is the equation of the circle with a center at `(-8 ,3 )` and a radius of `1`?

Answer 1

`(x+8)^2+(y-3)^2=1`

Explanation:

The standard equation for a circle with center `(a,b)` and radius `r` is
`color(white)("XXX")(x-a)^2+(y-b)^2=r^2`

Using the given values results in the equation given in the "Answer"
(and this would be my preferred form)

...but,
you might have a teacher who wants this in "general polynomial standard form";
in this case you need to expand the terms, arrange them in descending order of degree with the polynomial equated to `0`:
`color(white)("XXX")x^2+y^2+16x-6y+72=0`