What mass of water, H2O, can be produced from 150 grams of ammonia, NH3? Chemistry Stoichiometry Stoichiometry 1 Answer P dilip_k · Ernest Z. Feb 20, 2016 238 g Explanation: NH3+34O2=12N2+32H2O As guided by the above equation, we see 1 mole NH3 produces 1.5 moles of water. Hence 150 g NH3=15017mol NH3 produces 15017⋅1.5 moles H2O which will have a mass 15017⋅1.5×molar mass of H2O =15017⋅1.5⋅18=238 Answer link Related questions How do you solve a stoichiometry problem? What is stoichiometry? Question #93ac6 Why do we study stoichiometry? How many grams of NaOH is produced from 1.20x102 grams of Na2O? Na2O+H2O→2NaOH How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 See all questions in Stoichiometry Impact of this question 2634 views around the world You can reuse this answer Creative Commons License