What mass of water, H_2O, can be produced from 150 grams of ammonia, NH_3? Chemistry Stoichiometry Stoichiometry 1 Answer P dilip_k · Ernest Z. Feb 20, 2016 238 g Explanation: NH_3+3/4O_2 =1/2N_2+3/2H_2O As guided by the above equation, we see 1 mole "NH"_3 produces 1.5 moles of water. Hence "150 g NH"_3 =150/17 "mol NH"_3 produces 150/17*1.5 moles "H"_2"O" which will have a mass 150/17*1.5 × "molar mass of H"_2"O" =150/17*1.5*18=238 Answer link Related questions How do you solve a stoichiometry problem? What is stoichiometry? Question #93ac6 Why do we study stoichiometry? How many grams of NaOH is produced from 1.20 x 10^2 grams of Na_2O? Na_2O + H_2O -> 2NaOH How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 See all questions in Stoichiometry Impact of this question 2631 views around the world You can reuse this answer Creative Commons License