What is the mass of #3.21 * 10^-2# mol #Ni#? Chemistry Stoichiometry Stoichiometry 1 Answer Abdul Sammad Feb 22, 2016 #1.8939 g# Explanation: put the formula #mols=massdividear# then rearrange the formula and multiply the mols with the ar of nickel which is 59 so #59*3.21^10-2# and the ans will be #1.8939g# Answer link Related questions How do you solve a stoichiometry problem? What is stoichiometry? Question #93ac6 Why do we study stoichiometry? How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 See all questions in Stoichiometry Impact of this question 5772 views around the world You can reuse this answer Creative Commons License