How many grams of #(NH_4)_2SO_4# are present in .100 moles of #(NH_4)_2SO_4# ?

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Answer 1 · 2016-02-23T09:03:56

Ammonium sulfate has an equivalent weight of #132.14# #g*mol^-1#.

You have a #0.100# #mol# quantity.

#0.100# #cancel(mol)# #xx# #132.14# #g*cancel(mol^-1)# #=# #??# #g#.

Answer 2 · 2016-02-23T10:39:40

The mass in grams of 0.100 mol #"(NH"_4)_2"SO"_4"# is 13.2 g.

The molar mass of #"(NH"_4)_2"SO"_4"# is needed, which is #"132.13952 g/mol"#. http://pubchem.ncbi.nlm.nih.gov/compound/6097028#section=Top

To determine the mass of 0.100 mol ammonium sulfate, multiply the given mole by its molar mass.

#0.100 cancel(mol (NH_4)_2SO_4)xx(132.13952 g (NH_4)_2SO_4)/(1 cancel(mol (NH_4)_2SO_4))=13.2 g (NH_4)_2SO_4"# (rounded to three significant figures)