A parallelogram has sides A, B, C, and D. Sides A and B have a length of #2 # and sides C and D have a length of # 7 #. If the angle between sides A and C is #(5 pi)/6 #, what is the area of the parallelogram?

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Answer 1 · 2016-02-24T10:54:04

Area of the parallelogram is #7#.

Area of a parallelogram with sides #a# and #b# and angle #theta# between them is given by #a*b*sintheta#

Hence area of parallelogram in the given case is

#2*7*sin((5pi)/6)#, but as #sin((5pi)/6)=sin(pi/6)=1/2#

Area of parallelogram is #2*7*1/2=7#