Question

If sides A and B of a triangle have lengths of 9 and 7 respectively, and the angle between them is `(3pi)/8`, then what is the area of the triangle?

Answer 1

If the angle between two sides A,B be `theta` the area of the triangle will be = `1/2*A*B*sintheta`
here A = 9 unit
B = 7 unit
And `theta=3pi/8`
So area `=1/2*9*7*sin(3pi/8)`=29.10 squnit