What are the components of the vector between the origin and the polar coordinate #(6, (17pi)/12)#?
1 Answer
Mar 7, 2016
Explanation:
Using the formulae that links Polar to Cartesian coordinates.
#• x = rcostheta#
#• y = rsintheta # here r = 6 and
#theta = (17pi)/12# hence
#x = 6cos((17pi)/12) ≈ - 1.553# and
# y = 6sin((17pi)/12) ≈ -5.796 #
