What are the components of the vector between the origin and the polar coordinate $(- 9, \frac{5 π}{6})$ $(-9, (5pi)/6)$ ?

Question

What are the components of the vector between the origin and the polar coordinate $(- 9, \frac{5 π}{6})$ $(-9, (5pi)/6)$ ?

1 Answer

Impact of this question

1817 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-07T21:20:07

$x = 9 \cdot \frac{\sqrt{3}}{2}$ $x=9*sqrt3/2$
$y = - \frac{9}{2}$ $y=-9/2$

Explanation:

$r = - 9 θ = \frac{5 π}{6}$ $r=-9" "theta=(5pi)/6$
$x = r \cdot cos θ y = r \cdot sin θ$ $x=r*cos theta" "y=r*sin theta$
$θ = \frac{5 π}{6} \cdot \frac{180}{π} = 150^{o}$ $theta=(5pi)/6*180/pi=150^o$
$x = - 9 \cdot cos 150$ $x=-9*cos 150$
$x = 9 \cdot \frac{\sqrt{3}}{2}$ $x=9*sqrt3/2$
$y = - 9 \cdot sin 150$ $y=-9*sin150$
$y = - 9 \cdot \frac{1}{2}$ $y=-9*1/2$
$y = - \frac{9}{2}$ $y=-9/2$

Science

Math

Humanities

... and beyond

What are the components of the vector between the origin and the polar coordinate $(- 9, \frac{5 π}{6})$ $(-9, (5pi)/6)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What are the components of the vector between the origin and the polar coordinate (-9, (5pi)/6)(−9,5π6)(-9, (5pi)/6)?

1 Answer

Explanation:

Related questions

Impact of this question

What are the components of the vector between the origin and the polar coordinate $(- 9, \frac{5 π}{6})$ $(-9, (5pi)/6)$ ?