What volume of ammonia, in #cm^3#, can be prepared by reacting 20 #cm^3# of nitrogen gas with 30 #cm^3# of hydrogen gas?
Assuming that all volume are measured at the same temperature and pressure and the reaction goes to completion.
A. 20
B. 30
C. 40
D. 50
The answer given is A. 20, why?
Assuming that all volume are measured at the same temperature and pressure and the reaction goes to completion.
A. 20
B. 30
C. 40
D. 50
The answer given is A. 20, why?
1 Answer
The volume of ammonia that can be prepared is
Explanation:
This looks like a limiting reactant problem involving volumes of gases.
That means that we must use Gay-Lussac's Law of Combining Volumes: "The ratio between the volumes of the reactant gases and the products can be expressed in simple whole numbers".
Step 1. Write the balanced chemical equation.
The equation for the reaction is
The coefficients of the balanced equation tell us that the ratio is 1:3:2.
Hence, we can say that
Step 2. Identify the limiting reactant.
From
From
You can't get more than
By the time you have formed that amount, all the