How do you factor: #y= x^3 - 4x^2 + 4x - 16 #?
1 Answer
Mar 12, 2016
Factor by grouping to find:
#y = x^3-4x^2+4x-16#
#=(x^2+4)(x-4)#
#=(x-2i)(x+2i)(x-4)#
Explanation:
Factor by grouping:
#y = x^3-4x^2+4x-16#
#=(x^3-4x^2)+(4x-16)#
#=x^2(x-4)+4(x-4)#
#=(x^2+4)(x-4)#
That's as far as you can go with Real coefficients:
If you allow Complex coefficients then we can go a little further:
#=(x^2-(2i)^2)(x-4)#
#=(x-2i)(x+2i)(x-4)#
