Question

What is the trigonometric form of `13 e^( ( pi)/12 i )`?

Answer 1

`13e^(pi/12i)=13(cos(pi/12)+isin(pi/12))`

Explanation:

Euler's identity is a special case of Euler's formula from complex analysis, which states that for any real number x,
`e^{ix} = cos x + isin x`

`13e^(pi/12i)=13(cos(pi/12)+isin(pi/12))`