What is the vertex form of #y= 35x^2 - 22x + 3 #?

1 Answer

the vertex form
#(x-11/35)^2=1/35(y--16/35)#

Explanation:

From the given, perform completing the square
#y=35x^2-22x+3#

#y=35(x^2-22/35x)+3#

Determine the constant to added and subtracted by using the numerical coefficient of x which 22/35. We divide 22/35 by 2 then square it#=(22/35div 2)^2=121/1225#

#y=35(x^2-22/35x+121/1225-121/1225)+3#

#y=35(x^2-22/35x+121/1225)-35*121/1225+3#

#y=35(x-11/35)^2-121/35+3#

#y=35(x-11/35)^2+(-121+105)/35#

#y=35(x-11/35)^2-16/35#

#y+16/35=35(x-11/35)^2#

#(x-11/35)^2=1/35(y--16/35)#

God bless....I hope the explanation is useful.