Question

How do you find the vertex and the intercepts for `F(x)=x^2-4x-7`?

Answer 1

Vertex is (2, `-`11). y-intercept is `-7`, This parabola cuts x-axis at `(2+-sqrt11, 0)`. The length in-between is 2`sqrt11`. .

Explanation:

The equation has the form `(x-2)^2=y+11`.

This represents the parabola with vertex at (2, `-`11).

The axis of the parabola is the line x = 2, from the vertex in the positive direction of the y-axis.

To get intercept on the x-axis, put y = 0 in the equation and find x.

For the y-intercept put xo 0.,