Question

How do you use Heron's formula to determine the area of a triangle with sides of that are 7, 5, and 11 units in length?

Answer 1

`a=5, b=7, c=11, s=(a+b+c)/2=23/2`. Then Heron's Formula gives an area of `\sqrt{(23/2)(13/2)(9/2)(1/2)}=(3/4)\sqrt{299}` square units.

Explanation:

Heron's Formula is `Area=\sqrt{s(s-a)(s-b)(s-c)}` where a, b, c are the sides and s is half their sum.