Question

How do you divide `(1-2i)/(1-3i)` in trigonometric form?

Answer 1

`7/10+1/10*i`

Explanation:

`((1-2i)*(1+3i))/((1-3i)*(1+3i))`
`=(1+3i-2i-6i^2)/(1^2-3i^2)`
`=(1+3i-2i+6)/(1+9)`
`=7/10+1/10*i`