Question

If a `10kg` object moving at `7 m/s` slows down to a halt after moving `5/2 m`, what is the friction coefficient of the surface that the object was moving over?

Answer 1

considering conservation of mechanical energy
wirk done against frictional force = KE of the body
`mumgxxs=1/2mxxv^2`
`mu = v^2/(2gs)=7^2/(2xx9.8xx5/2)=1`