How do you find the vertex and the intercepts for #y = -2x^2 + 13x - 6#?
1 Answer
Apr 7, 2016
Explanation:
x-coordinate of vertex:
y-coordinate of vertex:
Vertex
To find y-intercept, make x = 0 --> y = -6.
To find x-intercepts, make y = 0 and solve the quadratic equation
There are 2 real roots (x-intercepts):
graph{-2x^2 + 13x - 6 [-40, 40, -20, 20]}