How do you write #f(x) = x^2+2x-8# in vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Alan P. Apr 8, 2016 vertex form: #(x-color(red)(color(white)("")(-1)))^2+color(blue)(color(white)("")(-9))# with vertex at #(color(red)(-1),color(blue)(-9))# Explanation: General vertex form: #color(white)("XXX")y=color(green)(m)(x-color(red)(a))^2+color(blue)(b)# with vertex at #(color(red)(a),color(blue)(b))# #f(x)=x^2+2x-8# #rarr f(x)=x^2+2x+1 -9# #rarr f(x)=(x+1)^2-9# #rarr f(x)=color(green)(1)(x-color(red)(color(white)("")(-1)))^2+color(blue)(""(-9))color(white)("XXX")# (in complete vertex form) Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 4161 views around the world You can reuse this answer Creative Commons License