How do you factor $y = 3 x^{3} - 9 x^{2}$ $y=3x^3 - 9x^2$ ?

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Answer 1 · 2016-04-09T18:16:21

$y = 3 x^{2} (x - 3)$ $y=3x^2(x-3)$

$y = 3 \times x \times x \times x - 3 \times 3 \times x \times x$ $y=3xx x xx x xx x - 3xx3xx x xx x$

Separate the common terms, $3 \times x \times x = 3 x^{2}$ $3xx x xx x=3x^2$ and write the remaining terms in brackets:

$\Rightarrow y = 3 x^{2} (x - 3)$ $=>y=3x^2(x-3)$

How do you factor y=3x3−9x2y=3x^3 - 9x^2 ?