Question

A mass of 45.0 grams of aluminum will react with how many grams of zinc chloride?

Answer 1

`328.6 g/(mol)`

Explanation:

In order to solve this problem we need to begin with a balanced chemical equation.

Zinc Chloride `(ZnCl_2 - Zn^+2 and Cl^-1)`
Reacts with Aluminum in solution to form
Aluminum Chloride `(AlCl_3 - Al^+3 and Cl^-1)`

`2Al + 3ZnCl_2 -> 2AlCl_3 + 3Zn`

Now we must use stoichiometry to convert grams of Al to grams of ZnCl_2

molar mass of aluminum is `27.99 g/(mol)`

molar mass of zinc chloride is `136.29 g/(mol)`
Zn `65.39`
Cl `2(35.45) = 70.90`
`65.39 +70.90 = 136.329`

the mole ratio of `ZnCl_2` to `Al` is `3:2`

grams `->` moles `->` moles `->` grams

`45 g Al` x `(1 cancel(mol Al))/(27.99 cancel(g Al))` x `cancel(3 (mol ZnCl_2))/(2 cancel(mol Al))` x `(136.29 g ZnCl_2)/(1 cancel(mol ZnCl_2))` =

`(45(3)(136.29))/((27.99)(2))` = `328.6 g/(mol)`