A charge of $6 C$ $6 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $39 J$ $39 J$ to $33 J$ $33 J$ , what is the voltage between points A and B?

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Answer 1 · 2016-04-16T08:29:00

The voltage between A and B = energy change/ charge
$\frac{39 - 33}{6} \frac{J}{C} = 1 V$ $(39-33)/6J/C=1V$

A charge of 6 C6C6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 39 J39J39 J to 33 J33J33 J, what is the voltage between points A and B?