How do you solve #x-4=8+3x#?

1 Answer
Apr 24, 2016

#x=-6#

Explanation:

To solve the given problem, you want to move all variables with #x# to one side of the equation and all other terms without #x# to the other.

In your case, move all terms with #x# to the right side and the ones without to the left.

Starting with,

#x-4=8+3x#

Subtract #x# from both sides,

#x# #color(red)(-x)-4=8+3x# #color(red)(-x)#

#-4=8+2x#

Subtract #8# from both sides,

#-4# #color(red)(-8)=8# #color(red)(-8)+2x#

#-12=2x#

Divide both sides by #2#,

#color(red)(color(black)(-12)/2)=color(red)(color(black)(2x)/2)#

#color(green)(|bar(ul(color(white)(a/a)x=-6color(white)(a/a)|)))#