Question

How do you solve for x in `3x-q=5q`?

Answer 1

`x=2q`

Explanation:

As `3x-q=5q`, adding `=q` on both sides, we get

`3x-cancelq+cancelq=5q+q`

or `3x=6q`, now multiplying both sides by `1/3`, we get

`cancel3x xx1/cancel3=2cancel6qxx1/cancel3`

or `x=2q`