How do you factor $- 6 x^{2} + 6 x^{3}$ $-6x^2+6x^3$ ?

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How do you factor $- 6 x^{2} + 6 x^{3}$ $-6x^2+6x^3$ ?

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Answer 1 · 2016-05-03T15:08:05

$6 x^{2} (x - 1)$ $6x^2(x-1)$

Explanation:

First, you should try to 'pull out of the parentheses' as much as you can: in this case it's $6 x^{2}$ $6x^2$ . So we divide each monomial by $6 x^{2}$ $6x^2$ :
$- 6 x^{2} + 6 x^{3} = 6 x^{2} (- 1 + x)$ $-6x^2+6x^3=6x^2(-1+x)$ ,
We prefer the factors to be of the form $(x - something)$ $(x- text(something) )$ so here we can just rearrange the last factor to obtain $6 x^{2} (x - 1)$ $6x^2(x-1)$ .

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How do you factor $- 6 x^{2} + 6 x^{3}$ $-6x^2+6x^3$ ?

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How do you factor $- 6 x^{2} + 6 x^{3}$ $-6x^2+6x^3$ ?