Question

How do you write the Vertex form equation of the parabola `y = x^2-6x+8`?

Answer 1

`y = (x - 3)^2 - 1`

Explanation:

`y = x^2 - 6x + 8`
x-coordinate of vertex:
`x = -b/(2a) = 6/2 = 3`
y-coordinate of vertex:
y(3) = 9 - 18 + 8 = -1
Vertex (3, -1)
Vertex form:
`y = (x - 3)^2 - 1`