Question

How do you write the vertex form equation of the parabola `y=2x^2 +11x-6`?

Answer 1

`y =2(x + 11/4)^2 - 21 1/8`

Explanation:

`y = 2x^2 + 11x - 6" divide RHS by 2"`

`y = 2(x^2 + 11/2 " " - 3 " ") " leave spaces to add terms"`

`y = 2(x^2 + 11/2 + color(red)((11/4)^2) - 3 - color(red)( (11/4)^2))`
`" " 11/2 ÷ 2 = 11/4`

`y = 2[(x + 11/4)^2 -169/16]`

`y =2(x + 11/4)^2 - 2xx169/16`

`y =2(x + 11/4)^2 - 169/8 rArr y =2(x + 11/4)^2 - 21 1/8`