Question

How many milliliters of 12.0 M hydrochloric acid (`HCl`) is required to prepare 0.75 L of a 0.25 M solution of `HCl`?

Answer 1

16mL

Explanation:

We have to use the titration formula:
`M_aV_a=M_bV_b`
Now just plug it in.
`(12)(x)=(.75)(.25)`
`12x = .1875`
`x= 0.015625` liters
To convert liter to mL, multiply it by 1000, since 1 L= 1000 mL
Therefore, the answer rounded is about 16 mL