What is the period of the function #y=3 cos pi x#?

1 Answer
May 29, 2016

In a function of the form #y = asin(b(x - c)) + d# or #y = acos(b(x - c)) + d#, the period is given by evaluating the expression #(2pi)/b#.

Explanation:

#y = 3cos(pi(x))#

period = #(2pi)/pi#

period = #2#

The period is therefore 2.

Practice exercises:

  1. Consider the function #y = -3sin(2x - 4) + 1#. Determine the period.

  2. Determine the period of the following graph, knowing it represents a sinusoidal function.

Grapher

Good luck, and hopefully this helps!