A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $60$ and the height of the cylinder is $16$ . If the volume of the solid is $520 pi$ , what is the area of the base of the cylinder?

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Answer 1 · 2016-06-01T13:57:12

Area of the base is $(130pi)/9$

Let the area of the base of cylinder be $A$ .

Hence volume of cylinder is $Axx16=16A$

and volume of cone is $1/3xxAxx60=20A$

Hence total volume is $20A+16A=36A=520pi$

Therefore $A=(520pi)/36=(130pi)/9$

A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is 60 60 and the height of the cylinder is 16 16 . If the volume of the solid is 520 pi520 pi, what is the area of the base of the cylinder?