How do you integrate dy / (4(y^(1/2))? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Rafael Jun 3, 2016 1/2y^(1/2)+C Explanation: [1]" "intdy/(4(y^(1/2))) First you can bring 1/4 outside the integral symbol. [2]" "=1/4intdy/y^(1/2) Next, bring y^(1/2) to the numerator. [3]" "=1/4inty^(-1/2)dy Use the power rule: intx^ndx=x^(n+1)/(n+1)+C (where C is a constant) [4]" "=1/4*y^(-1/2+1)/(-1/2+1)+C [5]" "=1/4*y^(1/2)/(1/2)+C [6]" "=color(red)(1/2y^(1/2)+C) Answer link Related questions How do you evaluate the integral intx^3+4x^2+5 dx? How do you evaluate the integral int(1+x)^2 dx? How do you evaluate the integral int8x+3 dx? How do you evaluate the integral intx^10-6x^5+2x^3 dx? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of |x|? What is the integral of 3x? What is the integral of 4x^3? What is the integral of sqrt(1-x^2)? See all questions in Integrals of Polynomial functions Impact of this question 2433 views around the world You can reuse this answer Creative Commons License