Question

How do you evaluate `sin^-1(sin((-2pi)/3))`?

Answer 1

`-(2pi)/3`.

Explanation:

If y = f(x) and the inverse relation is `x = f^(-1)(y)`, then

`f(f^(-1)(y) )=y and f^(-1)(f(x))=x`. The operands are returned as the values.

Here, the operand is `-(2pi)/3`, and so, the value is `-(2pi)/3`.

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