Question

What is the vertex form of `y= (x -4)(x/2 - 2)`?

Answer 1

In vertex form `y=1/2(x-4)^2`

Explanation:

`y=(x-4)(x/2-2) = (x-4)*1/2(x-4) =1/2(x-4)^2` Vertex is at `4,0` graph{1/2(x-4)^2 [-10, 10, -5, 5]}[Ans]