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What is the slope and intercept of $x - 5 = 0$ $x-5 = 0$ ?

1 Answer

Jun 6, 2016

$y-intercept \to (x, y) = (0, - 5)$ $"y-intercept "->(x,y)=(0,-5)$

Slope is 1

Explanation:

Write as: $x - 5 = y$ $" "x-5=y$

Turn it round and we have the same thing

$y = x - 5$ $y=x-5$

Compare to $y = m x + c$ $y=mx+c$

where m is the gradient. It is known that $1 \times x = x$ $1xxx=x$ so the gradient m must be 1.

The slope is 1. This means that for every 1 along left to right the graph goes up 1.

The y intercept is at $x = 0$ $x=0$ so

$y = x - 5 becomes y = 0 - 5$ $y=x-5" becomes "y=0-5$

So the y intercept is at $y = - 5$ $y=-5$

To write this properly you would present it as

$y-intercept \to (x, y) = (0, - 5)$ $"y-intercept "->(x,y)=(0,-5)$

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