How do you factor $21 a - 49 b - 7 c$ $21a - 49b -7c$ ?

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Answer 1 · 2016-06-24T08:33:32

7(3a - 7b - c)

In each of the 3 terms there is a common factor of 7 which can be taken out.

hence 21a - 49b - 7c = 7 (3a - 7b - c) is the factorised form

How do you factor 21a - 49b -7c21a−49b−7c21a - 49b -7c?