Question

How do you factor completely `n^2 + 7n - 44`?

Answer 1

Find two numbers that multiply to `-44` and that add to `7`.

These two numbers are `11` and `-4`.

`n^2 + 7n - 44 = (n + 11)(n - 4)`

Hopefully this helps!

Answer 2

Notice that `7=11-4` hence

#n^2+7n-44=n^2+(11-4)n-44=n^2-4n+11n-44= n(n-4)+11(n-4)=(n+11)(n-4)#