How do you find the vertex and intercepts for #y = 1/20x^2#?
1 Answer
Jun 29, 2016
Vertex is at
y-intercept at
x-intercept (only one) at
Explanation:
One way to look at this is to considered the standard vertex form:
with vertex at
the given equation:
with vertex at
The y-intercept is the value of
The x-intercept(s) is(are) the value(s) of