Question

A chemistry teacher adds 50.0 mL of 1.50 M `H_2SO_4` solution to 200 mL of water. What is the concentration of the final solution?

Answer 1

`0.30*mol*L^-1` with respect to sulfuric acid.

Explanation:

`"Concentration"` `=` `"Moles of substance"/"Volume"`

`=` `(50xx10^-3Lxx1.50*mol*L^-1)/((50+200)xx10^-3*L)`

`=` `0.30*mol*L^-1"with respect to "H_2SO_4`.

What is the concentration with respect to `H_3O^+`?