Question

How do you factor `3x^3 + 2x^2 - 27x - 18`?

Answer 1

`3x^3+2x^2-27x-18=(x+3)(x-3)(3x+2)`

Explanation:

`3x^3+2x^2-27x-18`

= `x^2(3x+2)-9(3x+2)`

= `(x^2-9)(3x+2)`

= `(x^2-3x+3x-9)(3x+2)`

= `(x(x-3)+3(x-3))(3x+2)`

= `(x+3)(x-3)(3x+2)`