Question

A lab assistant needs to make up 6.00 liters of .100 M HCI solution. How many liters of 12.0 M HCl solution should she use?

Answer 1

A sufficiency, here `50*mL.`, i.e. `0.0500*L`

Explanation:

`"Moles of HCl"` `=` `6.00*Lxx0.100*mol*L^-1=0.600*mol`.

So we need a volume of conc. acid that contains `0.600*mol`.

`"Volume"` `="Amount in moles"/"Concentration"` `=` `(0.600*mol)/(12.0*mol*L^-1)xx1000*mL*L^-1` `=` `50*mL.`