Question

What is the vertex form of `y=x^2-6x+15`?

Answer 1

`y = (x - 3)^2 + 6`

Explanation:

x-coordinate of vertex:
`x = -b/(2a) = 6/2 = 3`
y-coordinate of vertex
`y(3) = 9 - 18 + 15 = 6`
vertex (3, 6)
Vertex form of y:
`y = (x - 3)^2 + 6`