How do you solve for R in #a= 2piR^2 + 2piRh#?
2 Answers
Jul 12, 2016
Explanation:
Notice we have a quadratic in R here:
We can use the quadratic formula:
In the second fraction, we can rewrite the denominator from
Our solution becomes:
Jul 12, 2016
Explanation:
We can now solve for